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JaneyH
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Member since July 2014 | Posted 9 years ago |  0 |
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Haha left school too many moons ago! Thank you I can use that formula from now on :) |
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Andy at GRG
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Member since March 2006 | Posted 9 years ago | 0 |
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Back to school Janey, it is tan(-1) 44/1609 i.e 1.5 degrees angle or i suppose in your nomencature 44/1609x100= 2.7 percent. Sounds small but isn't when youare running up it. 1609 metres in a mile by the way.
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JaneyH
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Member since July 2014 | Posted 9 years ago | 0 |
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Hi, new to the forum but been using GRG for a while now. Just wondering if anyone can shed light on how the climb rate of a measured route equates to its % gradient. For example, if I measure a hill and it gives me a climb rate of 44m/mile or a 13m climb, how do I convert this to a %? Thanks! |
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